Meaning
Removes and returns the last element from a list, modifying the list in place. Use when you need to both retrieve and discard the final item, e.g., implementing a stack.
Primary Function
List mutation and retrieval
Communicative Purpose
Efficiently remove and obtain the last element of a list, supporting LIFO behavior.
Pattern
result = container.pop()
Core Structure
... = ... .pop()
Função primária
List mutation and retrieval
Propósito comunicativo
Efficiently remove and obtain the last element of a list, supporting LIFO behavior.
Situações de gatilho
Data structures: using a list as a stack where you need to pop the top element; Algorithm implementation: depth‑first search backtracking requiring removal of the last visited node; Undo feature: reverting the most recent action by popping it from a history list
Contextos
Any Python code using lists as stacks, algorithms like depth-first search, parsing, etc.
Padrão
result = container.pop()
Estrutura central
... = ... .pop()
Slots de substituição
result: variable name to store popped item; container: list (or any sequence supporting pop).
Colocados típicos
- list.append()
- list.pop(index)
- collections.deque.pop()
Substituições comuns
- Using del container[-1] to remove without returning
- or container[-1] to peek.
Erros comuns
Assuming pop() returns the list itself, forgetting that it modifies the list, using pop on empty list raises IndexError.
Similar / contraste
list.pop(i) removes at arbitrary index; deque.pop() from right side; list.remove(value) removes by value.
Interferências
Coming from languages where pop returns the container (e.g., some stack APIs), expecting the list to be unchanged.
Família do chunk
- list.append
- list.pop(index)
- list.remove
- deque.pop
- deque.popleft
Nuance
pop() is O(1) for the end; pop(i) is O(n). Raises IndexError if list empty; use try/except or check length.
Efeito pragmático
Provides constant-time removal of the last element, enabling efficient stack implementations.
Dica de memória
Think of popping the top of a stack of plates.
Nota
Use pop() for efficient LIFO removal; remember it modifies the list in place and raises IndexError on empty list.
Upgrade path
Use collections.deque for O(1) pops from both ends: d = deque(); d.pop(); d.popleft()
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